Soal NETADMIN

1) A company has the following addressing scheme requirements:

-currently has 25 subnets
-uses a Class B IP address
-has a maximum of 300 computers on any network segment
-needs to leave the fewest unused addresses in each subnet

What subnet mask is appropriate to use in this company?
a. 255.255.240.0
b. 255.255.248.0
c. 255.255.254.0
d. 255.255.255.0
e. 255.255.255.128
f. 255.255.255.248
jawab : C
karena terdapat 300 komputer dalam satu network
jadi 2n-2 = 300, n = 9 (29-2 = 510), terdapat 9 bit 0, subnet masknya 11111111.1111111.11111110.00000000 = 255.255.254.0

2) Refer to the exhibit. Host A is being manually configured for connectivity to the LAN.
Which two addressing scheme combinations are possible configurations that can be applied
to the host for connectivity? (Choose two.)

a. Address - 192.168.1.14

Gateway - 192.168.1.33

b. Address - 192.168.1.45

Gateway - 192.168.1.33

c. Address - 192.168.1.32

Gateway - 192.168.1.33

d. Address - 192.168.1.82

Gateway - 192.168.1.65

e. Address - 192.168.1.63

Gateway - 192.168.1.65

f. Address - 192.168.1.70

Gateway - 192.168.1.65

jawab : D & F

IP memiliki 27 bit 1 sebagai net id, maka subnet 255.255.255.224.

subnetmask tersebut dapat memikili net id 192.168.0, 192.168.1.32, 192.168.1.64, ...., 192.168.1.224. karena ip (192.168.1.65/27) yang terhubung langsung dengan jaringan A maka gateway pada komputer A adalah 192.168.1.65/27. Dan ip pada host A ada pada range (192.168.66-192.168.1.94).

3) A NIC of a computer has been assigned an IP address of 172.31.192.166 with a mask of

255.255.255.248. To which subnet does the IP address belong?

a. 172.31.0.0

b. 172.31.160.0

c. 172.31.192.0

d. 172.31.248.0

e. 172.31.192.160

f. 172.31.192.248

jawab : E

Subnet 225.255.225.248 kemungkinan mempunyai net id 172.31.192.0, 172.31.192.8, ..., 172.31.192.160, ..., 172.31.192.248.

4) Which subnet masks would be valid for a subnetted Class B address? (Choose two.)

a. 255.0.0.0

b. 255.254.0.0

c. 255.224.0.0

d. 255.255.0.0

e. 255.255.252.0

f. 255.255.255.192

jawab : D & E

Karena subnet 255.255.0.0 merupakan default dari subnet kelas B, lalu 255.255.252.0 adalah subnet kelas B yang sudah melakukan subneting.

5) Which combination of network id and subnet mask correctly identifies all IP addresses

from 172.16.128.0 through 172.16.159.255?

a. 172.16.128.0 and 255.255.255.224

b. 172.16.128.0 and 255.255.0.0

c. 172.16.128.0 and 255.255.192.0

d.172.16.128.0 and 255.255.224.0

e. 172.16.128.0 and 255.255.255.192

jawab : C

Selisih dari 159-128 adalah 31 dari 2ⁿ-2 jadi n=6, net idnya 172.16.0.0, 172.16.64.0, 172.16.128.0, 172.16.192.0 dan memiliki subnet 11111111.11111111.11000000.00000000 atau 255.255.192.0.

6) Which type of address is 223.168.17.167/29?

a. host address

b. multicast address

c. broadcast address

d. subnetwork address

jawab: C

Broadcast memili 29 bit yang dimana 1 dipakai untuk net id, maka binernya 11111111.11111111.11111111.11111000.

IP 223.168.17.167 merupakan broadcast dari 223.168.17.160.

7) What is the correct number of usable subnetworks and hosts for the IP network address

192.168.99.0 subnetted with a /29 mask?

a. 6 networks / 32 hosts

b. 14 networks / 14 hosts

c. 30 networks / 6 hosts

d. 62 networks / 2 hosts

jawab : C

Karena bit 1 yang digunakan subnet id adalah 29, jadi binernya 1111111.1111111.1111111.11111000, dari 2ⁿ-2 (dengan n adalah bit 1) maka 2⁵-2 = 30 network dan 2ⁿ-2 (dengan n adalah bit 0) maka 2³-2 = 6 host.

8) Company XYZ uses a network address of 192.168.4.0. It uses the mask of

255.255.255.224 to create subnets. What is the maximum number of usable hosts in each

subnet?

a. 6

b. 14

c. 30

d. 62

jawab : C

subnet 225.255.255.224 maka binernya adalah 11111111.111111.1111111.11100000.

Dari 2ⁿ-2 (dengan n bit 0) maka 2⁵-2 = 30 host.

9) A company is planning to subnet its network for a maximum of 27 hosts. Which subnet

mask would provide the needed hosts and leave the fewest unused addresses in each subnet?

a. 255.255.255.0

b. 255.255.255.192

c. 255.255.255.224

d. 255.255.255.240

e. 255.255.255.248

jawab : C

Dari 2ⁿ-2 = 27, n = 5 ( dari 5 bit 0 )

Jadi binernya 1111111.1111111.11111111.1110000 atau 255.255.255.224.

10) An IP network address has been subnetted so that every subnetwork has 14 usable host IP

addresses. What is the appropriate subnet mask for the newly created subnetworks?

a. 255.255.255.128

b. 255.255.255.224

c. 255.255.255.240

d. 255.255.255.248

e. 255.255.255.252

jawab : C

Dari 2ⁿ-2 = 14, n = 4 ( dari 4 bit 0 )

Jadi binernya 1111111.11111111.11111111.11110000 atau 255.255.255.240.

11) A company is using a Class B IP addressing scheme and expects to need as many as 100

networks. What is the correct subnet mask to use with the network configuration?

a. 255.255.0.0

b. 255.255.240.0

c. 255.255.254.0

d. 255.255.255.0

e. 255.255.255.128

f. 255.255.255.192

jawab : C

Dari 2ⁿ-2 =100, n = 7 ( dari 7 bit 1 )

Jadi binernya 11111111.1111111.1111110.0000000 atau 255.255.254.0 yang merupakan kelas B.

12) Given a host with the IP address 172.32.65.13 and a default subnet mask, to which

network does the host belong?

a. 172.32.65.0

b. 172.32.65.32

c. 172.32.0.0

d. 172.32.32.0

jawab : A

255.255.255.0 merupakan kelas C

memiliki range IP dari 172.32.65 sampai 172.32.65.254.

13) What is the subnetwork number of a host with an IP address of 172.16.210.0/22?

a. 172.16.42.0

b. 172.16.107.0

c. 172.16.208.0

d. 172.16.252.0

e. 172.16.254.0

jawab : C

Memiliki 22 bit dan 1 menjadi net id

Jadi binernya 11111111.11111111.11111100.00000000 maka net idnya 172.16.0.0, 172.16.4.0, ..., 172.16.208.0, ..., 172.16.252.0.

14) Which of the following IP addresses fall into the CIDR block of 115.64.4.0/22? (Choose

three.)

a. 115.64.8.32

b. 115.64.7.64

c. 115.64.6.255

d. 115.64.3.255

e. 115.64.5.128

f. 115.64.12.128

jawab : B, C & E

Memiliki 22 bit dan 1 menjadi net id

Jadi binernya 1111111.1111111.11111100.0000000

maka net idnya 115.64.0.0, 115.64.4.0, ..., 115.64.252.0

dan memiliki range net id 115.64.4.0 ( 115.64.4.1 - 115.64.7.254 ).

15) What is the subnetwork address for a host with the IP address 200.10.5.68/28?

a. 200.10.5.56

b. 200.10.5.32

c. 200.10.5.64

d. 200.10.5.0

jawab : C

Memiliki 28 bit dan 1 menjadi net id

Jadi binernya 11111111.11111111.11111111.11110000

Maka net idnya 200.10.5.0, 200.10.5.16, 200.10.5.32, 200.10.32.64, ..., 200.10.5.192.

16) The network address of 172.16.0.0/19 provides how many subnets and hosts?

a. 7 subnets, 30 hosts each

b. 7 subnets, 2046 hosts each

c. 7 subnets, 8190 hosts each

d. 8 subnets, 30 hosts each

e. 8 subnets, 2046 hosts each

f. 8 subnets, 8190 hosts each

jawab : F

Memiliki 19 bit maka binernya 11111111.1111111.11100000.00000000

Dari 2ⁿ jadi 2³ = 8 subnet, dan 2ⁿ-2 jadi 2¹³-2 = 8190 host.

17) You need 500 subnets, each with about 100 usable host addresses per subnet. What mask

will you assign using a Class B network address?

a. 255.255.255.252

b. 255.255.255.128

c. 255.255.255.0

d. 255.255.254.0

jawab : B

Binernya 11111111.11111111.11111111.10000000 atau 255.255.255.128

Dari 2ⁿ-2 = 100, n = 7 ( n adalah jumlah bit 0 yg digunakan ).

18) What is the subnetwork number of a host with an IP address of 172.16.66.0/21?

a. 172.16.36.0

b. 172.16.48.0

c. 172.16.64.0

d. 172.16.0.0

jawab : C

Memiliki 21 bit dan 1 menjadi net id

Jadi binernya 11111111.11111111.11111000.00000000

Maka net idnya 172.16.0.0, 172.16.8.0, ..., 172.16.64.0, ..., 172.16.248.0.

19) What mask would you assign to the network ID of 172.16.0.0 if you needed about 100

subnets with about 500 hosts each?

a. 255.255.255.0

b. 255.255.254.0

c. 255.255.252.0

d. 255.255.0.0

jawab : C

Binernya 11111111.1111111.11111110.00000000 atau 255.255.252.0

Dari 2ⁿ-2 = 500, n = 9 (n adalah jumlah bit 0 yg digunakan).

20) You need to configure a server that is on the subnet 192.168.19.24/29. The router has the

first available host address. Which of the following should you assign to the server?

a. 192.168.19.0 255.255.255.0

b. 192.168.19.33 255.255.255.240

c. 192.168.19.26 255.255.255.248

d. 192.168.19.31 255.255.255.248

e. 192.168.19.34 255.255.255.240

jawab : E

192.168.19.24/29 255.255.255.240 karena memiliki net id 192.168.19.0, 192.168.19.8, ..., 192.168.19.32.0, ..., 192.168.19.248.

21) You need a minimum of 300 subnets with a maximum of 50 hosts per subnet. Which of

the following masks will support the business requirements? (Choose two.)

a. 255.255.255.0

b. 255.255.255.128

c. 255.255.252.0

d. 255.25.255.224

e. 255.255.255.192

f. 255.255.248.0

jawab : B & E

Jadi binernya 11111111.11111111.11111111.11000000 atau 255.255.255.192

Dari 2ⁿ-2 >= 50, n = 6 ( n adalah jumah bit 0 yg digunakan )

Jumlah host minimum adalah 255.255.255.128 atau 11111111.11111111.11111111.10000000.

22) If an Ethernet port on a router were assigned an IP address of 172.16.112.1/25, what

would be the valid subnet address of this host?

a. 172.16.112.0

b. 172.16.0.0

c. 172.16.96.0

d. 172.16.255.0

e. 172.16.128.0

jawab : A

Memiliki 25 bit dan 1 menjadi net id

Maka binernya 11111111.11111111.11111111.10000000

Jadi net idnya 172.16.112.0, 172.16.112.128.

23) Refer to the exhibit. The internetwork in the exhibit has been assigned the IP address

172.20.0.0. What would be the appropriate subnet mask to maximize the number of networks

available for future growth?

a. 255.255.224.0

b. 255.255.240.0

c. 255.255.248.0

d. 255.255.252.0

e. 255.255.254.0

jawab : D

Dari 2^n-2 = 850, n = 10 ( n adalah jumlah bit 0 )

Maka binernya 11111111.11111111.11111100.00000000 atau 255.255.252.0.

24) You have a network with a subnet of 172.16.17.0/22. Which are valid host addresses?

a. 172.16.17.1 255.255.255.252

b. 172.16.0.1 255.255.240.0

c. 172.16.20.1 255.255.254.0

d. 172.16.16.1 255.255.255.240

e. 172.16.18.255 255.255.252.0

f. 172.16.0.1 255.255.255.0

jawab : A

Memiiliki 22 bit

Maka binernya 11111111.1111111.11111100.0000000 atau 255.255.252.0.

25) Your router has the following IP address on Ethernet0: 172.16.112.1/20. How many hosts

can be accommodated on the Ethernet segment?

a. 1024

b. 2046

c. 4094

d. 4096

e. 8190

jawab : C

Memiliki 20 bit

Maka binernya 11111111.11111111.11110000.00000000

Dari 2ⁿ-2 ( n bit 0 ) maka 2¹²-1 = 4094 host.

26) You have a /27 subnet mask. Which of the following are valid hosts? (Choose three.)

a. 11.244.18.63

b. 90.10.170.93

c. 143.187.16.56

d. 192.168.15.87

e. 200.45.115.159

f. 216.66.11.192

jawab : B, C & D

Memiliki 27 bit

Maka binernya 11111111.1111111.11111111.11100000

Net id yang dapat ditemukan dari w.x.y.0, w.x.y.32, w.x.y.64, w.x.y.128. w.x.y.160, w.x.y.192, w.x.y.224

27) You have a Class B network ID and need about 450 IP addresses per subnet. What is the

best mask for this network?

a. 255.255.240.0

b. 255.255.248.0

c. 255.255.254.0

d. 255.255.255.0

jawab : C

Dari 2ⁿ-2 = 450, n = 9 ( n adalah bit 0)

maka binernya 11111111.11111111.11111110.00000000 atau 255.255.254.0

28) Host A is connected to the LAN, but it cannot connect to the Internet. The host

configuration is shown in the exhibit. What are the two problems with this configuration?

(Choose two.)

a. The host subnet mask is incorrect.

b. The host is not configured for subnetting.

c. The default gateway is a network address.

d. The default gateway is on a different network than the host.

e. The host IP address is on a different network from the Serial interface of the router.

Jawab : D & E

IP address pada host berbeda dgn IP pada router.

IP router merupakan gateway yang IP nya antara 198.18.166.66 – 192.18.166.78.